What happens if you invoked the component function directly in React?: Let's take a look at this example:
const ExampleComponent = () => {
const [input, setInput] = useState("");
//do something here
};
export const App = () => {
const [show, setShow] = useState(false);
return (
<div>
<button onClick={() => setShow(!show)} />
{show && ExampleComponent()}
</div>
);
};
//This will trigger error "Render more hooks than during the previous render"
//Solution: use <ExampleComponent /> instead
So why does this happen?
-
By doing so, you are essentially integrating ExampleComponent and App into a super component and treating ExampleComponent as a custom hook that is executed immediately before the return statement, which means that whenever some states in ExampleComponent change, the entire App re-renders.
-
The first time the App renders, the show state is false therefore the ExampleComponent doesn't render and only use 1 hook.
-
When we click the button, the show state is true which makes the ExampleComponent render and trigger the second hook in the ExampleComponent which violates React rule of hooks.
How to avoid it?
- Use React Component Syntax which translate into React.createElement(ExampleComponent, null) making the properties of that component in the VDOM tree controlled by the ExampleComponent.
